document.write( "Question 311717: log(2x-3)+ log(x-2)=2logx
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document.write( "Please solve for x and show the work thank you \n" );
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Algebra.Com's Answer #222968 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! log(2x-3)+ log(x-2) = 2log(x) \n" ); document.write( ": \n" ); document.write( "log((2x-3)*(x-2)) = log(x^2) \n" ); document.write( "FOIL \n" ); document.write( "log(2x^2-4x-3x+6) = log(x^2) \n" ); document.write( ": \n" ); document.write( "log(2x^2 - 7x + 6) = log(x^2) \n" ); document.write( "therefore \n" ); document.write( "2x^2 - 7x + 6 = x^2 \n" ); document.write( ": \n" ); document.write( "2x^2 - x^2 - 7x + 6 = 0 \n" ); document.write( ": \n" ); document.write( "x^2 - 7x + 6 = 0 \n" ); document.write( "Factor \n" ); document.write( "(x - 6)(x - 1) = 0 \n" ); document.write( "Two solutions \n" ); document.write( "x = 6 \n" ); document.write( "and \n" ); document.write( "x = 1 \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check both solutions in original problem \n" ); document.write( "log(2x-3)+ log(x-2) = 2log(x) \n" ); document.write( "x=6 \n" ); document.write( "log(2(6)-3)+ log(6-2) = 2log(6) \n" ); document.write( "log(9) + log(4) = log(6^2) \n" ); document.write( "log(36) = log(36) \n" ); document.write( "x = 6; a good solution \n" ); document.write( ": \n" ); document.write( "x=1, not a solution, the log of a negative number not permitted \n" ); document.write( " \n" ); document.write( " |