document.write( "Question 36391: math099 find two consecutive odd integers such that twice the square of the first plus the square of the second totals ninety-nine. \n" ); document.write( "
Algebra.Com's Answer #22294 by vidhyak(98)\"\" \"About 
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find two consecutive odd integers such that twice the square of the first plus the square of the second totals ninety-nine.\r
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\n" ); document.write( "\n" ); document.write( "Let the 2 odd integers be x, x+2
\n" ); document.write( "equation is \r
\n" ); document.write( "\n" ); document.write( "2x^2 + (x + 2)^2 = 99
\n" ); document.write( "2x^2 + x^2 + 4x + 4 = 99
\n" ); document.write( "3x^2 + 4x + 4 = 99
\n" ); document.write( "3x^2 + 4x - 95 = 0
\n" ); document.write( "3x^2 + 19x - 15x - 95 = 0
\n" ); document.write( "x(3x + 19) - 5 (3x + 19) = 0
\n" ); document.write( "(x - 5)(3x + 19) = 0\r
\n" ); document.write( "\n" ); document.write( "x = 5, -19/3\r
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\n" ); document.write( "\n" ); document.write( "Since x is a integer x = 5
\n" ); document.write( "and the other integer is 7\r
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\n" ); document.write( "\n" ); document.write( "Verify
\n" ); document.write( "2x^2 + (x + 2)^2 = 99
\n" ); document.write( "2(5)^2 + (7)^2 = 99
\n" ); document.write( "2(25) + 49 = 99
\n" ); document.write( "50 + 49 = 99
\n" ); document.write( "99 = 99
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