document.write( "Question 311642: a total of $8000 is invested into two simple interest accounts. On one account the annual simple interest rate is 9%; on the second account the annual simple interest rate is 7% How much should be invested in the 7% account so that the total interest earned is 8.5% of the total investment? \n" ); document.write( "
Algebra.Com's Answer #222928 by mananth(16946)\"\" \"About 
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a total of $8000 is invested into two simple interest accounts. On one account the annual simple interest rate is 9%; on the second account the annual simple interest rate is 7% How much should be invested in the 7% account so that the total interest earned is 8.5% of the total investment?
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\n" ); document.write( "Let $x be the investment in 7% account
\n" ); document.write( "8000-x will be invested in 9%
\n" ); document.write( "Total invested = $ 8000
\n" ); document.write( "you should get 8.5%
\n" ); document.write( "..
\n" ); document.write( "0.07x +0.09(8000-x)=8000*0.085
\n" ); document.write( "0.07x+720-0.09x=680
\n" ); document.write( "-0.02x=680-720
\n" ); document.write( "x=-40/-0.02
\n" ); document.write( "x= $2000
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