document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=311660>Question 311660</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Question 1-Etch Clean Graphics uses one cleanser\r<BR>\n" );
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document.write( "that is 25% acid and a second that is 50% acid. How\r<BR>\n" );
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document.write( "many liters of each should be mixed to get 10 L of a\r<BR>\n" );
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document.write( "solution that is 40% acid?\r<BR>\n" );
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document.write( "Question 2-Automotive Maintenance. \"Arctic Antifreeze\" is 18% alcohol and \"Frost No-More\" is 10% alcohol. How many liters of Arctic Antifreeze should be mixed with 7.5 L of Frost No-More in order to get a mixture that is 15% alcohol?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #222927 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=222927\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Question 1-Etch Clean Graphics uses one cleanser\r<BR>\n" );
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document.write( "that is 25% acid and a second that is 50% acid. How\r<BR>\n" );
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document.write( "many liters of each should be mixed to get 10 L of a\r<BR>\n" );
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document.write( "solution that is 40% acid?<BR>\n" );
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document.write( "cleanser A 25% acid - x liters<BR>\n" );
document.write( "cleanser B 50% acid -10-x liters<BR>\n" );
document.write( "Total 10 liters 40%<BR>\n" );
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document.write( "Concentration of A +concentration of B = Total concentration of mixture<BR>\n" );
document.write( "0.25x+0.5(10-x)=0.4*10<BR>\n" );
document.write( "0.25x+5-0.5x=4<BR>\n" );
document.write( "-0.25x=-1<BR>\n" );
document.write( "x=-1/-0.25<BR>\n" );
document.write( "x=4 liters 25% & 6 liters 50%<BR>\n" );
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document.write( "Question 2-Automotive Maintenance. \"Arctic Antifreeze\" is 18% alcohol and \"Frost No-More\" is 10% alcohol. How many liters of Arctic Antifreeze should be mixed with 7.5 L of Frost No-More in order to get a mixture that is 15% alcohol?<BR>\n" );
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document.write( "arctic antifreeze 18% - x liters<BR>\n" );
document.write( "Frost no-more 10%,  7.5 liters<BR>\n" );
document.write( "Total x+7.5 liters , 15%<BR>\n" );
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document.write( "0.18x+0.1*7.5 = 0.15(x+7.5)<BR>\n" );
document.write( "0.18x+0.75=0.15x+1.125<BR>\n" );
document.write( "0.18x-0.15x=1.125-0.75<BR>\n" );
document.write( "0.03x=0.375<BR>\n" );
document.write( "x=0.375/0.03<BR>\n" );
document.write( "x=12.5 liters\r<BR>\n" );
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document.write( "CHECK<BR>\n" );
document.write( "(0.18*12.5)+(0.1*7.5)=3 </SPAN>\n" );
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