document.write( "Question 311542: A handful of 65 coins consist of pennies, nickles, and dimes. The number of nickels is 4 less than twice the number of pennies, and there are 13 more dimes than nickles. how many coins of each kind are there?\r
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Algebra.Com's Answer #222876 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! n=2p-4 \n" ); document.write( "d=n+13 or d=(2p-4+13) \n" ); document.write( "p+n+d=65 \n" ); document.write( "p+(2p-4)+(2p-4+13)=65 \n" ); document.write( "5p-4-4+13=65 \n" ); document.write( "5p=65+4+4-13 \n" ); document.write( "5p=60 \n" ); document.write( "p=60/5 \n" ); document.write( "p=12 pennies. \n" ); document.write( "n=2*12-4 \n" ); document.write( "n=24-4=20 nickles. \n" ); document.write( "d=20+13=33 dimes. \n" ); document.write( "Proof: \n" ); document.write( "12+20+33=65 \n" ); document.write( "65=65 \n" ); document.write( " |