document.write( "Question 311542: A handful of 65 coins consist of pennies, nickles, and dimes. The number of nickels is 4 less than twice the number of pennies, and there are 13 more dimes than nickles. how many coins of each kind are there?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #222876 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
n=2p-4
\n" ); document.write( "d=n+13 or d=(2p-4+13)
\n" ); document.write( "p+n+d=65
\n" ); document.write( "p+(2p-4)+(2p-4+13)=65
\n" ); document.write( "5p-4-4+13=65
\n" ); document.write( "5p=65+4+4-13
\n" ); document.write( "5p=60
\n" ); document.write( "p=60/5
\n" ); document.write( "p=12 pennies.
\n" ); document.write( "n=2*12-4
\n" ); document.write( "n=24-4=20 nickles.
\n" ); document.write( "d=20+13=33 dimes.
\n" ); document.write( "Proof:
\n" ); document.write( "12+20+33=65
\n" ); document.write( "65=65
\n" ); document.write( "
\n" );