document.write( "Question 311607: Bill has a pocket full of nickels, dimes and quarters totaling $3.45. The number of dimes is 5 times the number of nickels. The number of quarters is 7 less than 3 times the number of nickels. How many of each kind does Bill have? \r
\n" ); document.write( "\n" ); document.write( "Tried this way and it did not work D 5x(10) N x Q 3x-7
\n" ); document.write( "50x+ x + 75x-7 = 345
\n" ); document.write( "126x-7=345
\n" ); document.write( " +7 +7
\n" ); document.write( "126x/126=352/126
\n" ); document.write( "x=2.79\r
\n" ); document.write( "\n" ); document.write( "Can you please explain what it is I am doing wrong?
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Algebra.Com's Answer #222871 by Edwin McCravy(20081) $\"\"$ $\"About$

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Bill has a pocket full of nickels, dimes and quarters totaling $3.45. The number of dimes is 5 times the number of nickels. The number of quarters is 7 less than 3 times the number of nickels. How many of each kind does Bill have?
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document.write( "Tried this way and it did not work  D 5x(10) N x  Q 3x-7\r\n" );
document.write( "50x+ x + 75x-7 = 345\r\n" );
document.write( "126x-7=345\r\n" );
document.write( "    +7   +7\r\n" );
document.write( "126x/126=352/126\r\n" );
document.write( "x=2.79\r\n" );
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document.write( "Can you please explain what it is I am doing wrong?\r\n" );
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document.write( "The number of dimes is given in terms of the number of nickels.\r\n" );
document.write( "The number of quarters is also given in terms of the nuber of nickels.\r\n" );
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document.write( "So we let x = the number of nickels\r\n" );
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document.write( "Since

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\n" ); document.write( "\n" ); document.write( "The number of dimes is 5 times the number of nickels.
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document.write( "Number of dimes = 5x\r\n" );
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document.write( "Since

\r
\n" ); document.write( "\n" ); document.write( "TThe number of quarters is 7 less than 3 times the number of nickels.
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document.write( "Number of quarters = 3x - 7\r\n" );
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document.write( "So, since\r\n" );
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\n" ); document.write( "dimes and quarters totaling $3.45
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document.write( "5(Number of nickels) + 10(Number of dimes) + 25(Number of quarters) = 345\r\n" );
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document.write( "5x + 10(5x) + 25(3x - 7) = 345\r\n" );
document.write( "   5x + 50x  + 75x - 175 = 345\r\n" );
document.write( "              130x - 175 = 345\r\n" );
document.write( "              130x - 175 = 345\r\n" );
document.write( "                    130x = 345 + 175\r\n" );
document.write( "                    130x = 520\r\n" );
document.write( "                    x = \r\n" );
document.write( "                    x = 4\r\n" );
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document.write( "Number of nickels = x = 4\r\n" );
document.write( "Number of dimes = 5x = 5(5) = 20\r\n" );
document.write( "Number of quarters = 3x - 7 = 3(4) - 7 = 12 - 7 = 5  \r\n" );
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document.write( "You made two mistakes.  \r\n" );
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document.write( "1. You had just x where you should have had 5x (5 cents in a nickel)\r\n" );
document.write( "2. When you had 25(3x - 7) you multiplied the 25 by the 3x but forgot\r\n" );
document.write( "   to multiply the 25 by the -7 so you had 75x - 7 where you should have \r\n" );
document.write( "   had 75x - 175.\r\n" );
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document.write( "Edwin

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