document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=311570>Question 311570</A>: <I><SPAN STYLE=\"word-break: break-all;\"> jimmy is a partner in an internet based coffee supplier. The company offers gourmet coffee beans for $11 per pound and regular coffee beans for $4 per pound. Jimmy is creating a medium price product that sell for $6 per pound. The first thing to go into the mixing bin was 12 pounds of gourmet coffee beans. How many pounds of the less expensive regular beans should be added </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #222864 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=222864\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 12*11+4x=6(12+x)<BR>\n" );
document.write( "132+4x=72+6x<BR>\n" );
document.write( "4x-6x=72-132<BR>\n" );
document.write( "-2x=-60<BR>\n" );
document.write( "x=-60/-2<BR>\n" );
document.write( "x=30 lbs. of the $4 coffee is added.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "12*11+4*30=6(12+30)<BR>\n" );
document.write( "132+120=6*42<BR>\n" );
document.write( "252=252 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );