Algebra.Com's Answer #222842 by nerdybill(7384)  You can put this solution on YOUR website! I'll assume you meant log base 2: \n" );
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document.write( "Solve by applying the quadratic formula. Doing so yields: \n" );
document.write( "x = {1.685, -10.685} \n" );
document.write( "The negative solution is an extraneous solution leaving: \n" );
document.write( "x = 1.685 \n" );
document.write( "Details of quadratic follows: \n" );
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document.write( " Solved by pluggable solver: SOLVE quadratic equation with variable | \n" );
document.write( "Quadratic equation (in our case ) has the following solutons: \n" );
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document.write( " For these solutions to exist, the discriminant should not be a negative number. \n" );
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document.write( " First, we need to compute the discriminant : . \n" );
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document.write( " Discriminant d=153 is greater than zero. That means that there are two solutions: . \n" );
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document.write( " Quadratic expression can be factored: \n" );
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document.write( " Again, the answer is: 1.68465843842649, -10.6846584384265.\n" );
document.write( "Here's your graph: \n" );
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