document.write( "Question 311559: An object is thrown downward from a plane which is 540 feet above the ground. The object is thrown with an initial velocity of 27 ft/sec. The distance traveled by the object in t seconds is s = 16t2 + 27t, where s is in feet. How long does it take the object to reach the ground? Show your work. \r
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document.write( "I need help i understand that \r
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document.write( "540 = 16t^2 + 27t but what is after this I am lost. Please help me if you can \n" );
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Algebra.Com's Answer #222835 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! 540 = 16t^2 + 27t \n" ); document.write( "Considering up to be positive, it's \n" ); document.write( "h(t) = -16t^2 - 27t + 540 = 0 \n" ); document.write( "
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