document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=311556>Question 311556</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The base of a triagle is 6cm greater than the height. The area is 36cm^2. Find the height and the length of the base. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #222831 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=222831\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The base of a triangle is 6cm greater than the height. The area is 36cm^2. Find the height and the length of the base.<BR>\n" );
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document.write( "Area = (1/2)bh<BR>\n" );
document.write( "36 = (1/2)*(h+6)h<BR>\n" );
document.write( "h^2 + 6h - 72 = 0<BR>\n" );
document.write( "Factor:<BR>\n" );
document.write( "(x+12)(x-6) = 0<BR>\n" );
document.write( "Positive solution:<BR>\n" );
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document.write( "h = 6 (height)<BR>\n" );
document.write( "h+6 = 12 (base)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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