document.write( "Question 311546: Please help! The ancient Greeks thought that the
\n" ); document.write( "most pleasing shape for a rectangle was one for which the
\n" ); document.write( "ratio of the length to the width was approximately 8 to 5,
\n" ); document.write( "the golden ratio. If the length of a rectangular painting is
\n" ); document.write( "2 ft longer than its width, then for what dimensions would
\n" ); document.write( "the length and width have the golden ratio?
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Algebra.Com's Answer #222828 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
The ancient Greeks thought that the
\n" ); document.write( "most pleasing shape for a rectangle was one for which the
\n" ); document.write( "ratio of the length to the width was approximately 8 to 5,
\n" ); document.write( "the golden ratio. If the length of a rectangular painting is
\n" ); document.write( "2 ft longer than its width, then for what dimensions would
\n" ); document.write( "the length and width have the golden ratio?
\n" ); document.write( ":
\n" ); document.write( "Here's one way
\n" ); document.write( ":
\n" ); document.write( "Let x = the multiplier
\n" ); document.write( "then
\n" ); document.write( "8x = the length
\n" ); document.write( "and
\n" ); document.write( "5x = the width
\n" ); document.write( ":
\n" ); document.write( "\" length of a rectangular painting is 2 ft longer than its width,\"
\n" ); document.write( "8x = 5x + 2
\n" ); document.write( "8x - 5x = 2
\n" ); document.write( "3x = 2
\n" ); document.write( "x = \"2%2F3\" is the multiplier
\n" ); document.write( "then
\n" ); document.write( "8*\"2%2F3\" = \"16%2F3\" = 5\"1%2F3\" ft is the length
\n" ); document.write( "and
\n" ); document.write( "5*\"2%2F3\" = \"10%2F3\" = 3\"1%2F3\" ft is the width
\n" ); document.write( ":
\n" ); document.write( "We can see there is a 2' difference
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