document.write( "Question 311314: Stever can tape and mud the drywall of a room in 6 hours. Mike can do it in 4 hours. Mike joins Steve an hour after Steve starts and together they worked finishing the job. How long did each one work? \n" ); document.write( "
Algebra.Com's Answer #222827 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Steve can tape and mud the drywall of a room in 6 hours. \n" ); document.write( " Mike can do it in 4 hours. \n" ); document.write( " Mike joins Steve an hour after Steve starts and together they worked finishing the job. \n" ); document.write( " How long did each one work? \n" ); document.write( ": \n" ); document.write( "Let t = Mikes working time \n" ); document.write( "then \n" ); document.write( "(t+1) = Steve's working time \n" ); document.write( ": \n" ); document.write( "Let the completed job = 1 \n" ); document.write( ": \n" ); document.write( "A shared work equation \n" ); document.write( " \n" ); document.write( "multiply equation by 12, results \n" ); document.write( "2(t+1) + 3t = 12 \n" ); document.write( ": \n" ); document.write( "2t + 2 + 3t = 12 \n" ); document.write( ": \n" ); document.write( "2t + 3t = 12 - 2 \n" ); document.write( ": \n" ); document.write( "5t = 10 \n" ); document.write( "t = \n" ); document.write( "t = 2 hrs is Mike's working time \n" ); document.write( "and \n" ); document.write( "2 + 1 = 3 hrs is Steve's working time \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution \n" ); document.write( " |