document.write( "Question 311523: how do you solve a problem like this:
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document.write( "One pipe can fill a reservoir 1 hr faster than another pipe. Together they can fill the reservoir in 4 hrs. How long to the nearest tenth of an hour does it take the faster pipe to fill the reservoir by itself? \n" );
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Algebra.Com's Answer #222819 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! One pipe can fill a reservoir 1 hr faster than another pipe. Together they can fill the reservoir in 4 hrs. How long to the nearest tenth of an hour does it take the faster pipe to fill the reservoir by itself? \n" ); document.write( ". \n" ); document.write( "Let x = rate of slower pipe \n" ); document.write( "then \n" ); document.write( "x-1 = rate of faster pipe \n" ); document.write( ". \n" ); document.write( "4(1/x + 1/(x-1)) = 1 \n" ); document.write( "4((x-1) + x) = x(x-1) \n" ); document.write( "4(2x-1) = x(x-1) \n" ); document.write( "8x-4 = x^2-x \n" ); document.write( "-4 = x^2-9x \n" ); document.write( "0 = x^2-9x+4 \n" ); document.write( "Because we can't factor, we must resort to the quadratic formula. Doing so yields: \n" ); document.write( "x = {0.5, 8.5} \n" ); document.write( "Tossing out the 0.5 (because calculating the faster pipe will produce a negative answer) leaves: \n" ); document.write( "x = 8.5 hrs \n" ); document.write( ". \n" ); document.write( "Time for faster pipe to fill: 8.5-1 = 7.5 hours \n" ); document.write( ". \n" ); document.write( "Details of quadratic follows: \n" ); document.write( "
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