document.write( "Question 311479: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 40 miles per hour and train B is traveling at 48 miles per hour. Train A passes a station ar 1:25 a.m. If train B passes the same station at 1:40 a.m., at what time will train B catch up to train A? \n" ); document.write( "
Algebra.Com's Answer #222799 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Train A speed = 40 mph \n" ); document.write( "Train B 48 mph\r \n" ); document.write( "\n" ); document.write( "Train A is ahead of train B at the station by 15 minutes.( 1/4 hour)\r \n" ); document.write( "\n" ); document.write( "By the time train B reaches the station train A has traveled 40 * 1/4 miles \n" ); document.write( "=10 miles to a point say P.\r \n" ); document.write( "\n" ); document.write( "Let the distance from point P to the point where train B overtakes train A be x \n" ); document.write( ". \n" ); document.write( "Train B travels 10 + x miles in the same time the train A travels x miles\r \n" ); document.write( "\n" ); document.write( "time taken by train A = x/40 hours \n" ); document.write( "time taken by train B = x+10 / 48 \n" ); document.write( ". \n" ); document.write( "x/40 = x+10 /48 \n" ); document.write( "48x= 40(x+10) \n" ); document.write( "48x=40x +400 \n" ); document.write( "8x= 400 \n" ); document.write( "x= 50\r \n" ); document.write( "\n" ); document.write( "time taken by train A t travel 50 miles = 50/40 \n" ); document.write( "=5/4 hours= 75 minutes \n" ); document.write( "This is the same time taken by train B to cross train A \r \n" ); document.write( "\n" ); document.write( "Add 75 minutes to the time when Train B was at the station. You know what to do\r \n" ); document.write( "\n" ); document.write( "That is the time train B catches up \n" ); document.write( " \n" ); document.write( " |