document.write( "Question 311141: Train a leaves a station traveling at 96 kilometers per hour. 4 hours later train b leaves the same station traveling in the same direction at 107 kilometers per hour. How long does it take train b to cath up to train a? \n" ); document.write( "
Algebra.Com's Answer #222774 by ankor@dixie-net.com(22740)\"\" \"About 
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Train a leaves a station traveling at 96 kilometers per hour.
\n" ); document.write( " 4 hours later train b leaves the same station traveling in the same direction at 107 kilometers per hour.
\n" ); document.write( " How long does it take train b to catch up to train a?
\n" ); document.write( ":
\n" ); document.write( "let t = time for b to catch a
\n" ); document.write( "then
\n" ); document.write( "(t+4) = travel time of train a, when it's caught
\n" ); document.write( ":
\n" ); document.write( "When b catch a, they will have traveled the same distance
\n" ); document.write( "write a distance equation: dist = speed * time
\n" ); document.write( ":
\n" ); document.write( "107t = 96(t+4)
\n" ); document.write( "107t = 96t + 384
\n" ); document.write( "107t - 96t = 384
\n" ); document.write( "11t = 384
\n" ); document.write( "t = \"384%2F11\"
\n" ); document.write( "t = 34.91 hrs for b to catch a
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "Check solution by finding the distance for each
\n" ); document.write( "107*34.91 = 3735.37 km
\n" ); document.write( "96*38.91 = 3735.36 km, close enough \n" ); document.write( "
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