document.write( "Question 311431: Solve 4y ^2 = 12\r
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document.write( "I've done this and was wondering if I was on the right path:\r
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document.write( "4y ^2 = 12
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document.write( "4y^2 - 12 = 0
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document.write( "(2y - 4)( 2y + 3) = 0
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document.write( "2y -4 = 0
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document.write( "add 4
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document.write( "2y = 4
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document.write( "divide by 2
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document.write( "y = 2\r
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document.write( "2y + 3 = 0
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document.write( "subtract 3
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document.write( "2y = -3
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document.write( "y = -3 /2\r
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Algebra.Com's Answer #222750 by JBarnum(2146)![]() ![]() You can put this solution on YOUR website! (2y - 4)( 2y + 3) = 0\r \n" ); document.write( "\n" ); document.write( "did u realize what this foils in to? 4y^2-y-12=0 so this would be incorrect \n" ); document.write( "id simply do this: \n" ); document.write( " \n" ); document.write( "divide by 4 \n" ); document.write( " \n" ); document.write( "sqrt each side \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |