document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=311423>Question 311423</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One liter of 70% alcohol is needed. How much of 95% alcohol could be used to satisfy the 70% originally required? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #222744 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=222744\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assuming it's diluted with something with no alcohol:<BR>\n" );
document.write( "1 liter of 70% --> 0.7 liters of alcohol<BR>\n" );
document.write( "0.7/0.95 =~ 0.7368 liters of 95% + 0.2602 liters of dilutant (water or tonic water)\r<BR>\n" );
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