document.write( "Question 36335: I'm having truble here...apply the quadratic formula to find the roots of the given function, and then graph the function.\r
\n" ); document.write( "\n" ); document.write( "f(x) = x^2 + 4 \n" ); document.write( "

Algebra.Com's Answer #22265 by Earlsdon(6294) $\"\"$ $\"About$

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Solve $\"f%28x%29+=+x%5E2%2B4\"$ by the quadratic formula: $\"x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a\"$ \r
\n" ); document.write( "\n" ); document.write( "If you write your equation in the standard form: $\"ax%5E2%2Bbx%2Bc=0\"$ you will see that a = 1, b = 0, and c = 4, so applying the quadratic formula:
\n" ); document.write( " $\"x+=+%28-0%2B-sqrt%280%5E2-4%281%29%284%29%29%29%2F2%281%29\"$
\n" ); document.write( " $\"x+=+%28-0%2B-sqrt%28-16%29%29%2F2\"$
\n" ); document.write( " $\"x+=+4sqrt%28-1%29%2F2\"$ and $\"x+=+-4sqrt%28-1%29%2F2\"$
\n" ); document.write( " $\"x+=+2sqrt%28-1%29\"$ and $\"x+=+-2sqrt%28-1%29\"$ Simplify. $\"sqrt%28-1%29+=+i\"$
\n" ); document.write( " $\"x+=+2i\"$ and $\"x+=+-2i\"$ These are the roots.\r
\n" ); document.write( "\n" ); document.write( "The graph:
\n" ); document.write( " $\"graph%28300%2C200%2C-5%2C5%2C-5%2C10%2Cx%5E2%2B4%29\"$
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