document.write( "Question 311313: Solve x^2 - 2x = 24 by factoring. \n" ); document.write( "
Algebra.Com's Answer #222647 by fractalier(6550)\"\" \"About 
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Starting from
\n" ); document.write( "x^2 - 2x = 24
\n" ); document.write( "let's bring the 24 to the left side by subtracting 24 from both sides
\n" ); document.write( "x^2 - 2x - 24 = 0
\n" ); document.write( "Now set up your parentheses
\n" ); document.write( "( )( ) = 0
\n" ); document.write( "Since it begins with x^2, we know it must be
\n" ); document.write( "(x )(x ) = 0
\n" ); document.write( "Now look at the second sign. It is a minus. That means our binomials have different signs...
\n" ); document.write( "(x+ )(x- ) = 0
\n" ); document.write( "Then we ask: What are the factors of 24 that have a difference of 2?
\n" ); document.write( "Well, 6 and 4, and since the middle term is minus 2x, the 6 goes to the negative term, and we get
\n" ); document.write( "(x+4)(x-6) = 0
\n" ); document.write( "If these multiply to make zero, then either must be zero, so that
\n" ); document.write( "x = -4 and x = 6
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