document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=311262>Question 311262</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the answer to this problem? <BR>\n" );
document.write( "2x+5y=-16  <BR>\n" );
document.write( "y=-20-6x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #222631 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=222631\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let us use the substitution method for this one...from<BR>\n" );
document.write( "2x+5y=-16  <BR>\n" );
document.write( "y=-20-6x<BR>\n" );
document.write( "we can substitute -20-6x in for \"y\" in the first equation and get<BR>\n" );
document.write( "2x + 5(-20-6x) = -16<BR>\n" );
document.write( "2x - 100 - 30x = -16<BR>\n" );
document.write( "-28x - 100 = -16<BR>\n" );
document.write( "-28x = 84<BR>\n" );
document.write( "x = -3<BR>\n" );
document.write( "If x = -3, we can substitute into the second equation and get y...<BR>\n" );
document.write( "y = -20 - 6(-3)<BR>\n" );
document.write( "y = -20 + 18<BR>\n" );
document.write( "y = -2  </SPAN>\n" );
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