document.write( "Question 36300: use the discriminant to determine the number of solutions of the quadratic equation, and whether the solutions are real or complex. Note: It is not necessary to find the roots; just determine the number and types of solutions.\r
\n" ); document.write( "\n" ); document.write( "2x^2 + x - 1 = 0
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Algebra.Com's Answer #22262 by Nate(3500)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"2x%5E2%2B1x%2B-1+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%281%29%5E2-4%2A2%2A-1=9\".
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\n" ); document.write( " Discriminant d=9 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-1%2B-sqrt%28+9+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%281%29%2Bsqrt%28+9+%29%29%2F2%5C2+=+0.5\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%281%29-sqrt%28+9+%29%29%2F2%5C2+=+-1\"
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\n" ); document.write( " Quadratic expression \"2x%5E2%2B1x%2B-1\" can be factored:
\n" ); document.write( " \"2x%5E2%2B1x%2B-1+=+2%28x-0.5%29%2A%28x--1%29\"
\n" ); document.write( " Again, the answer is: 0.5, -1.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+2%2Ax%5E2%2B1%2Ax%2B-1+%29\"

\n" ); document.write( "\n" ); document.write( "....since the discriminant is greater than 0, the answers are either two rational or irrational real numbers....
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