document.write( "Question 311190: find the quotient for (14y+8y^2+y^3+12)÷(6+y) \n" ); document.write( "
Algebra.Com's Answer #222610 by Fombitz(32388)\"\" \"About 
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\"%28y%5E3%2B8y%5E2%2B14y%2B12%29%2F%28y%2B6%29\"
\n" ); document.write( "First factor \"y%5E2\"
\n" ); document.write( "\"y2%28y%2B6%29=y%5E3%2B6y%5E2\"
\n" ); document.write( "Subtracted from the original polynomial gives a remainder of,
\n" ); document.write( "\"%28y%5E3%2B8y%5E2%2B14y%2B12%29-%28y%5E3%2B6y%5E2%29=2y%5E2%2B14y%2B12\"
\n" ); document.write( "Second factor \"2y\"
\n" ); document.write( "\"2y%28y%2B6%29=2y%5E2%2B12y\"
\n" ); document.write( "Subtracted from the previous remainder gives a new remainder of,
\n" ); document.write( "\"%282y%5E2%2B14y%2B12%29-%282y%5E2%2B12y%29=2y%2B12\"
\n" ); document.write( "Third factor: \"2\"
\n" ); document.write( "\"2%28y%2B6%29=2y%2B12\"
\n" ); document.write( "Subtracted from the previous remainder gives a remainder of 0.
\n" ); document.write( "\"2y%2B12-%282y%2B12%29=0\"\r
\n" ); document.write( "\n" ); document.write( "Gather up all of the factors.
\n" ); document.write( "\"%28y%5E3%2B8y%5E2%2B14y%2B12%29%2F%28y%2B6%29=y%5E2%2B2y%2B2\"
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