document.write( "Question 311182: I really need help with the steps to this equation, I really dont know what I'm doing and would really like to learn before my exam on monday. this is the problem:solving inconsistent systems and dependent systems/ 3x - y =7
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document.write( " 14x + 6 =2y
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Algebra.Com's Answer #222585 by mananth(16949) You can put this solution on YOUR website! 3x - y =7 \n" ); document.write( "14x + 6 =2y \n" ); document.write( ". \n" ); document.write( "Let us put the equation in order with variables on left side and number on the right side.\r \n" ); document.write( "\n" ); document.write( "3x-y=7 \n" ); document.write( "14x-2y=-6. \n" ); document.write( ". \n" ); document.write( "(In practical terms when the terms or numbers cross over to the other side their signs change. This is not applicable for division)\r \n" ); document.write( "\n" ); document.write( "Lets eliminate y\r \n" ); document.write( "\n" ); document.write( "Multiply the first equation by -2 and add the two equations\r \n" ); document.write( "\n" ); document.write( "-2(3x-y)+14x-2y=-2*7-6 \n" ); document.write( "-6x+2y+14x-2y=-20 \n" ); document.write( "8x=-20 \n" ); document.write( "x=-5/2\r \n" ); document.write( "\n" ); document.write( "plug the value of x in any equation \n" ); document.write( "14*-5/2 -2y=-6 \n" ); document.write( "-35-2y=-6 \n" ); document.write( "-2y=29 \n" ); document.write( "y=-29/2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |