document.write( "Question 311236: how much pure alcohol must be added to 15 oz of a 60% solution of rubbing alcohol to change it to a 70% solution? \n" ); document.write( "
Algebra.Com's Answer #222580 by mananth(16946)\"\" \"About 
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let quantity of 100% alcohol required be x oz\r
\n" ); document.write( "\n" ); document.write( "rubbing alcohol = 60% 15 oz\r
\n" ); document.write( "\n" ); document.write( "Mixture 70% alcohol quantity = (x+15) oz\r
\n" ); document.write( "\n" ); document.write( "add the concentrations of individual and equate it to total concentration
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\n" ); document.write( "1x+0.6*15 =0.7(x+15)\r
\n" ); document.write( "\n" ); document.write( "x+9=0.7x +10.5\r
\n" ); document.write( "\n" ); document.write( "x-0.7x = 10.5-9
\n" ); document.write( "0.3x = 1.5
\n" ); document.write( "x=5 oz of pure alcohol
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