document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=311208>Question 311208</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the maximum perimeter of a rectangle with an area of 84 square inches? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #222559 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=222559\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A = L*W\r<BR>\n" );
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document.write( "84 = LW\r<BR>\n" );
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document.write( "At this point, you can solve for either L or W. \r<BR>\n" );
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document.write( "I will solve for W.\r<BR>\n" );
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document.write( "84 - L = W\r<BR>\n" );
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document.write( "The perimeter of a rectangle is found using P = 2L + 2W.\r<BR>\n" );
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document.write( "P = 2L + 2(84 - L)\r<BR>\n" );
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document.write( "P = 2L + 168 - 2L\r<BR>\n" );
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document.write( "P = 168 inches </SPAN>\n" );
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