document.write( "Question 311163: W angle is 30o more than its complement.\r
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document.write( "b. Three times an angle is 12o less than its supplement.rite an equation for each statement.\r
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document.write( "a. Twice an\r
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document.write( "i don't understand how to write the equation at all. \n" );
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Algebra.Com's Answer #222556 by checkley77(12844) ![]() You can put this solution on YOUR website! a. Twice an angle is 30o more than its complement. \n" ); document.write( "2x=(90-2x)+30 \n" ); document.write( "2x=90-2x+30 \n" ); document.write( "2x+2x=90+30 \n" ); document.write( "4x=120 \n" ); document.write( "x=120/4 \n" ); document.write( "x=30 is the smaller angle. \n" ); document.write( "2*30=(90-2*30)+30 \n" ); document.write( "60=90-60+30 \n" ); document.write( "60=120-60 \n" ); document.write( "60=60\r \n" ); document.write( "\n" ); document.write( "b. Three times an angle is 12o less than its supplement. \n" ); document.write( "3x=(180-3x)-12 \n" ); document.write( "3x=180-3x-12 \n" ); document.write( "3x+3x=180-12 \n" ); document.write( "6x=168 \n" ); document.write( "x=168/6=28 ans. for the smaller angle. \n" ); document.write( "3*28=189-3*28-12 \n" ); document.write( "84=180-84-12 \n" ); document.write( "84=180-96 \n" ); document.write( "84=84 \n" ); document.write( " |