document.write( "Question 311163: W angle is 30o more than its complement.\r
\n" ); document.write( "\n" ); document.write( "b. Three times an angle is 12o less than its supplement.rite an equation for each statement.\r
\n" ); document.write( "\n" ); document.write( "a. Twice an\r
\n" ); document.write( "\n" ); document.write( "i don't understand how to write the equation at all.
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Algebra.Com's Answer #222556 by checkley77(12844)\"\" \"About 
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a. Twice an angle is 30o more than its complement.
\n" ); document.write( "2x=(90-2x)+30
\n" ); document.write( "2x=90-2x+30
\n" ); document.write( "2x+2x=90+30
\n" ); document.write( "4x=120
\n" ); document.write( "x=120/4
\n" ); document.write( "x=30 is the smaller angle.
\n" ); document.write( "2*30=(90-2*30)+30
\n" ); document.write( "60=90-60+30
\n" ); document.write( "60=120-60
\n" ); document.write( "60=60\r
\n" ); document.write( "\n" ); document.write( "b. Three times an angle is 12o less than its supplement.
\n" ); document.write( "3x=(180-3x)-12
\n" ); document.write( "3x=180-3x-12
\n" ); document.write( "3x+3x=180-12
\n" ); document.write( "6x=168
\n" ); document.write( "x=168/6=28 ans. for the smaller angle.
\n" ); document.write( "3*28=189-3*28-12
\n" ); document.write( "84=180-84-12
\n" ); document.write( "84=180-96
\n" ); document.write( "84=84
\n" ); document.write( "
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