document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=311090>Question 311090</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help with title: solving systems by elimination<BR>\n" );
document.write( "A chemist has a beaker of a 3% acid solution and a beaker of a 7% acid solution.  He needs to make 75ml of a 4% acid solution.  complete the table.\r<BR>\n" );
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document.write( "		   3% solutiom	+	7% solution	=	4% solution<BR>\n" );
document.write( "Amt of solution	         x	+	    y	        =	<BR>\n" );
document.write( "Amt of acid (ml)	____x	+	____y	        =	<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #222509 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=222509\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .07X+.03(75-X)=.04*75<BR>\n" );
document.write( ".07X+2.25-.03X=3<BR>\n" );
document.write( ".04X=3-2.25<BR>\n" );
document.write( ".04X=.75<BR>\n" );
document.write( "X=.75/.04<BR>\n" );
document.write( "X=18.75 ml. OF 7% SOLUTION.<BR>\n" );
document.write( "75-18.75=56.25 ml. OF 3% SOLUTION.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( ".07*18.75+.03*56.25=.04*75<BR>\n" );
document.write( "1.3125+16.875=3<BR>\n" );
document.write( "3=3 </SPAN>\n" );
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