document.write( "Question 310986: The area of a rectangle is 60 in ^2. The length is 4 inches greater than the width. Find the length.\r
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\n" ); document.write( "\n" ); document.write( "a) 6 in.
\n" ); document.write( "b) 3 in.
\n" ); document.write( "c) 4 in.
\n" ); document.write( "d) 10 in.
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Algebra.Com's Answer #222503 by JBarnum(2146)\"\" \"About 
You can put this solution on YOUR website!
lw=60
\n" ); document.write( "l=4+w
\n" ); document.write( "w^2+4w=60
\n" ); document.write( "w^2+4w-60
\n" ); document.write( "w=6 l=10
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"aw%5E2%2Bbw%2Bc=0\" (in our case \"1w%5E2%2B4w%2B-60+=+0\") has the following solutons:
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\n" ); document.write( " \"w%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%284%29%5E2-4%2A1%2A-60=256\".
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\n" ); document.write( " Discriminant d=256 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-4%2B-sqrt%28+256+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"w%5B1%5D+=+%28-%284%29%2Bsqrt%28+256+%29%29%2F2%5C1+=+6\"
\n" ); document.write( " \"w%5B2%5D+=+%28-%284%29-sqrt%28+256+%29%29%2F2%5C1+=+-10\"
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\n" ); document.write( " Quadratic expression \"1w%5E2%2B4w%2B-60\" can be factored:
\n" ); document.write( " \"1w%5E2%2B4w%2B-60+=+1%28w-6%29%2A%28w--10%29\"
\n" ); document.write( " Again, the answer is: 6, -10.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B4%2Ax%2B-60+%29\"

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