document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=36221>Question 36221</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone show me how to simplify these 2 problems--please show me the steps\r<BR>\n" );
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document.write( "(2x)^2 * (3x^4)\r<BR>\n" );
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document.write( "and\r<BR>\n" );
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document.write( "(-3x divided by 2y^3)^-2\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #22250 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=22250\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (2X)~2*(3X~4 OR 4X~2*3X~4 OR 12X~5 MULTIPLY THE COEFFICIENTS 4*3=12 THE ADD THE POWERS OF X 2+3 OR X~5 THUS YOU HAVE 12X~5.\r<BR>\n" );
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document.write( "((-3)/(2Y~3))~2 OR (-3)~2=9 & (2Y~3)~2=4Y~6 THUS WE HAVE 9/4Y~6 </SPAN>\n" );
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