document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=310828>Question 310828</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much water must be added to 300ML of a 60% acid solution in order to dilute it to a solution of 45% acids? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #222294 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=222294\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How much water must be added to 300ML of a 60% acid solution in order to dilute it to a solution of 45% acids?<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
document.write( "0.60*300 + 0*x = 0.45(300+x)<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "60*300 + 0 = 45*300 + 45x<BR>\n" );
document.write( "45x = 15*300<BR>\n" );
document.write( "x = (1/3)(300)<BR>\n" );
document.write( "x = 100 ML (amt. of water that must be added to the mix)<BR>\n" );
document.write( "===================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );