document.write( "Question 310774: a crew team can row 48 km downstream in 4 hours, but it takes 6 hours to row that same distance upstream. find the rate the team rows in still water, and the rate of the river. \n" ); document.write( "

Algebra.Com's Answer #222269 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"s\"$ = the rate in still water
\n" ); document.write( "Let $\"r\"$ = the rate of the river
\n" ); document.write( "given:
\n" ); document.write( "Rate rowing downstream = $\"48%2F4+=+12\"$ km/hr
\n" ); document.write( "Time to row upstream = $\"6\"$ hrs
\n" ); document.write( "-----------------------------
\n" ); document.write( "Rowing downstream:
\n" ); document.write( " $\"48+=+12%2At%5Bd%5D\"$
\n" ); document.write( " $\"t%5Bd%5D+=+4\"$ hrs
\n" ); document.write( " $\"48+=+%28s+%2B+r%29%2A4\"$
\n" ); document.write( "Rowing upstream:
\n" ); document.write( " $\"48+=+%28s+-+r%29%2A6\"$
\n" ); document.write( "----------------
\n" ); document.write( " $\"4s+%2B+4r+=+6s+-+6r\"$
\n" ); document.write( " $\"2s+=+10r\"$
\n" ); document.write( " $\"s+=+5r\"$
\n" ); document.write( "and, since
\n" ); document.write( " $\"48+=+%28s+%2B+r%29%2A4\"$
\n" ); document.write( " $\"s+%2B+r+=+12\"$
\n" ); document.write( " $\"5r+%2B+r+=+12\"$
\n" ); document.write( " $\"6r+=+12\"$
\n" ); document.write( " $\"r+=+2\"$
\n" ); document.write( "and
\n" ); document.write( " $\"s+=+5r\"$
\n" ); document.write( " $\"s+=+10\"$
\n" ); document.write( "The rate the team rows in still water is 10 km/hr
\n" ); document.write( "The rate of the river is 2 km/hr \n" ); document.write( "

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