document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=310646>Question 310646</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 36 yards. The width is 18 yards less than twice the length. FInd the length and width of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #222266 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=222266\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=2L+2W<BR>\n" );
document.write( "W=2L-18<BR>\n" );
document.write( "36=2L+2(2L-18)<BR>\n" );
document.write( "36=2L+4L-36<BR>\n" );
document.write( "6L=36+36<BR>\n" );
document.write( "6L=72<BR>\n" );
document.write( "L=72/6<BR>\n" );
document.write( "L=12 ANS.<BR>\n" );
document.write( "W=2*12-18<BR>\n" );
document.write( "W=24-18=6 ANS FOR THE WIDTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "36=2*12+2*6<BR>\n" );
document.write( "36=24+12<BR>\n" );
document.write( "36=36 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );