document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=310783>Question 310783</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve for all values of &#952; for = the < 360 degrees, that satisfy the equation sec ^2 &#952; - 3=tan &#952; , to the nearest tenth of a degree </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #222263 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=222263\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve for all values of &#952; for = the < 360 degrees, that satisfy the equation sec ^2 &#952; - 3=tan &#952; , to the nearest tenth of a degree<BR>\n" );
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document.write( "sec^2(x) - 3 = tan(x)<BR>\n" );
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document.write( "Note: sec^2(x) = tan^2(x) + 1<BR>\n" );
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document.write( "tan^2(x) + 1 - 3 = tan(x)<BR>\n" );
document.write( "Rearrange:<BR>\n" );
document.write( "tan^2(x) - tan(x) -2 = 0<BR>\n" );
document.write( "Factor:<BR>\n" );
document.write( "(tan(x)-2)(tan(x)+1) = 0<BR>\n" );
document.write( "tan(x) = 2 or tan(x) = -1<BR>\n" );
document.write( "x = 63.43 degrees or x = 63.43+180 = 243.43 degrees<BR>\n" );
document.write( "x = 135 degrees or x = 315 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );