document.write( "Question 310653: The length of a rectangle is six feet more than the width, If the perimeter is 32 feet, what are the length and the width? \n" ); document.write( "
Algebra.Com's Answer #222261 by checkley77(12844)\"\" \"About 
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P=2L+2W
\n" ); document.write( "L=W+6
\n" ); document.write( "32=2(W+6)+2W
\n" ); document.write( "32=2W+12+2W
\n" ); document.write( "32=4W+12
\n" ); document.write( "4W=32-12
\n" ); document.write( "4W=20
\n" ); document.write( "W=20/4
\n" ); document.write( "W=5 ANS. FOR THE WIDTH.
\n" ); document.write( "L=5+6=11 ANS FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "32=2*11+2*5
\n" ); document.write( "32=22+10
\n" ); document.write( "32=32
\n" ); document.write( "
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