document.write( "Question 310653: The length of a rectangle is six feet more than the width, If the perimeter is 32 feet, what are the length and the width? \n" ); document.write( "
Algebra.Com's Answer #222261 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! P=2L+2W \n" ); document.write( "L=W+6 \n" ); document.write( "32=2(W+6)+2W \n" ); document.write( "32=2W+12+2W \n" ); document.write( "32=4W+12 \n" ); document.write( "4W=32-12 \n" ); document.write( "4W=20 \n" ); document.write( "W=20/4 \n" ); document.write( "W=5 ANS. FOR THE WIDTH. \n" ); document.write( "L=5+6=11 ANS FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "32=2*11+2*5 \n" ); document.write( "32=22+10 \n" ); document.write( "32=32 \n" ); document.write( " |