document.write( "Question 310704: how many millimeters of a 40 percent acid solutionn and how many of a 10 percent acid solution must be mixed together to produice 30 millimeters 20 percents solution \n" ); document.write( "
Algebra.Com's Answer #222256 by checkley77(12844)\"\" \"About 
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.40X+.10(30-X)=.20*30
\n" ); document.write( ".40X+3-.10X=6
\n" ); document.write( ".30X=6-3
\n" ); document.write( ".30X=3
\n" ); document.write( "X=3/.30
\n" ); document.write( "X=10 MILLIMETERS OF 40% ACID SOLUTION IS NEEDED.
\n" ); document.write( "PROOF:
\n" ); document.write( ".40*10+.10(30-10)=.20*30
\n" ); document.write( "4+.10*20=6
\n" ); document.write( "4+2=6
\n" ); document.write( "6=6\r
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