document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=310775>Question 310775</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve by elimination method.  Thank you - I am getting substitution but this is<BR>\n" );
document.write( "                                           really hard.\r<BR>\n" );
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document.write( "x+6y=16<BR>\n" );
document.write( "-x+6y=8   I did come up with 12y=8 and then I get stuck.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #222250 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=222250\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+6y=16<BR>\n" );
document.write( "-x+6y=8 <BR>\n" );
document.write( "I did come up with 12y=8 and then I get stuck.<BR>\n" );
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document.write( "Good so far:<BR>\n" );
document.write( "12y = 8<BR>\n" );
document.write( "y = 2/3<BR>\n" );
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document.write( "Substitute into x+6y = 16<BR>\n" );
document.write( "x + 6(2/3) = 16<BR>\n" );
document.write( "x + 4 = 16<BR>\n" );
document.write( "x = 12<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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