document.write( "Question 36280: y=x+1
\n" ); document.write( "y=-2x-4 please help??????
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Algebra.Com's Answer #22223 by vidhyak(98)\"\" \"About 
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y=x+1 --------equation 1
\n" ); document.write( "y=-2x-4 --------equation 2\r
\n" ); document.write( "\n" ); document.write( "Subtract eq 1 and eq 2
\n" ); document.write( "Y term gets cancelled and you get \r
\n" ); document.write( "\n" ); document.write( "(y-y) = x -(-2x) + 1-(-4)
\n" ); document.write( "0 = x+2x +1+4
\n" ); document.write( "3x + 5 = 0
\n" ); document.write( "3x = -5
\n" ); document.write( "x = -5/3\r
\n" ); document.write( "\n" ); document.write( "Substitute the value of x = -5/3 in eq 1.
\n" ); document.write( "y = x + 1
\n" ); document.write( "y = (-5/3) + 1
\n" ); document.write( "y = -2/3\r
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