document.write( "Question 310722: Solve the following equation algebraically for all values of theta in the interval 0 degrees is less than or equal to theta which is less than or equal to 180 degrees\r
\n" ); document.write( "\n" ); document.write( "2sintheta minus 1=0 \n" ); document.write( "

Algebra.Com's Answer #222228 by nyc_function(2741) $\"\"$ $\"About$

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We need to find values for theta (in degrees) that lie between 0 and 180 degrees. We are looking at the first and second quadrants only.\r
\n" ); document.write( "\n" ); document.write( "Let t = theta in the equation since I do not have a theta key on the keyboard.\r
\n" ); document.write( "\n" ); document.write( "2sin(t) - 1 = 0\r
\n" ); document.write( "\n" ); document.write( "Adding 1 to both sides we get:\r
\n" ); document.write( "\n" ); document.write( "2sin(t) = 1\r
\n" ); document.write( "\n" ); document.write( "Now divide both sides by 2.\r
\n" ); document.write( "\n" ); document.write( "sin(t) = 1/2\r
\n" ); document.write( "\n" ); document.write( "From the unit circle (that you should memorize), we learn that the values of theta when sine = 1/2 are: 30 degrees and 150 degrees.\r
\n" ); document.write( "\n" ); document.write( "NOTE: 30 degrees lies in quadrant 1 and 150 degrees lies in quadrant 2.\r
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