document.write( "Question 310647: 5. A researcher claims that the average age of people who buy lottery tickets is 65. A sample of 30 is selected and their ages are recorded as shown below. The standard deviation is 14. At α = 0.05 is there enough evidence to reject the researcher’s claim? Show all work.
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Algebra.Com's Answer #222186 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "x = 61.7, \"sigma\" = 14\r\n" );
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document.write( "\"H%5B0%5D\": \"mu=65\"\r\n" );
document.write( "\"H%5Ba%5D\": \"mu%3C%3E65\"\r\n" );
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document.write( "\"z=%28xBAR-mu%29%2F%28sigma%2Fsqrt%28n%29%29=%2861.7-65%29%2F%2814%2Fsqrt%2830%29%29=-1.29\"\r\n" );
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document.write( "No, we cannot reject the claim at \"alpha=0.05\" because z \r\n" );
document.write( "is neither less than -1.96 nor greater than 1.96.\r\n" );
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document.write( "We could also do it by computing the p-score, the probability\r\n" );
document.write( "that xBAR would be at least as far off from 65 as 61.7 if the mean \r\n" );
document.write( "were actually 65.     \r\n" );
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document.write( "To find that p-score we find the area to the left of the z-score -1.29\r\n" );
document.write( "as .5-.4015=.0985 and double it since this is a two-tail test.  That\r\n" );
document.write( "gives the p-score of .197.\r\n" );
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document.write( "So we would only reject the null hypothesis if it were that \"alpha%3E.197\".\r\n" );
document.write( "But \"alpha\" is lower that that, only .05.\r\n" );
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document.write( "Edwin
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