document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=310694>Question 310694</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two trains leave a station at the same time and are travelling in opposite directions. One is travelling at a rate of 35 km/h and the other is travelling at a rate of 65 km/h. In how many hours will the trains be 350 km apart?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #222176 by </B><A HREF=/tutors/aboutme.mpl?userid=texttutoring><B>texttutoring(324)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=texttutoring><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=texttutoring><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=222176\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You will need to use the formula D=VT, where D=distance, V=velocity (or speed) and T=time. I will use the subscript 1 or 2 to note which train I am talking about. (V1 = velocity of train 1, V2 = velocity of train 2, and so on)\r<BR>\n" );
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document.write( "Write down what you know:\r<BR>\n" );
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document.write( "V1=35 km/h<BR>\n" );
document.write( "V2 = 65km/h\r<BR>\n" );
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document.write( "Total Distance, D = 350 km\r<BR>\n" );
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document.write( "The total distance is just the sum of each train's distance, because they started at the same point and travelled in opposite directions.\r<BR>\n" );
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document.write( "D = D1 + D2\r<BR>\n" );
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document.write( "D = V1*t + V2*t<BR>\n" );
document.write( "350 = 35t + 65t<BR>\n" );
document.write( "350 = t(35+65)<BR>\n" );
document.write( "350 = 100t<BR>\n" );
document.write( "350/100 = t<BR>\n" );
document.write( "3.5 = t\r<BR>\n" );
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document.write( "The trains will be 350 km apart after 3.5 hours. </SPAN>\n" );
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