document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=310686>Question 310686</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two trains leave a station at the same time and are travelling in opposite directions. One is travelling at a rate of 35 km/h and the other is travelling at a rate of 65 km/h. In how many hours will the trains be 350 km apart? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #222159 by </B><A HREF=/tutors/aboutme.mpl?userid=loni1234><B>loni1234(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=loni1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=222159\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> v=speed<BR>\n" );
document.write( "s=the distance<BR>\n" );
document.write( "t=time\r<BR>\n" );
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document.write( "now the speed of the first train is v1=35km/h, the speed of the second train is 65km/h.\r<BR>\n" );
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document.write( "The distance for the first train is s1=v1*t and for the second train s2=v2*t<BR>\n" );
document.write( "The distance betwen them will be s=s1+s2, s=(v1*t)+(v2*t), s=(v1+v2)*t\r<BR>\n" );
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document.write( "t=s/(v1+v2)=350km/(65km/h+35km/h)=3.5hours   </SPAN>\n" );
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