document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=310633>Question 310633</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I can't remember how to solve the infinite series. \r<BR>\n" );
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document.write( "1. What is the solution to the infinite geometric series... the lower limit is = to 1. The upper limit is the infinite symbol. 0.8(0.2)^(n-1).\r<BR>\n" );
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document.write( "Now I know the formula is a1/1 - r. But I can't remember which goes for A1 and which goes for r.\r<BR>\n" );
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document.write( "2. What is the solution to the infinite geometric series... the lower limit is = to 1. The upper limit is the infinite symbol. (-2/3)^(n-1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #222128 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=222128\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. What is the solution to the infinite geometric series... the lower limit is = to 1. The upper limit is the infinite symbol. 0.8(0.2)^(n-1).<BR>\n" );
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document.write( "S = a(1)[1/(1-r)<BR>\n" );
document.write( "a(1) = 0.8(0.2)^(0) == 0.8<BR>\n" );
document.write( "r = 0.2<BR>\n" );
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document.write( "S = 0.8[1-0.2] = 1<BR>\n" );
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document.write( "2. What is the solution to the infinite geometric series... the lower limit is = to 1. The upper limit is the infinite symbol. (-2/3)^(n-1)<BR>\n" );
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document.write( "This series alternates : 1, -2/3, 4/9, -8/27, 16/81... etc.<BR>\n" );
document.write( "So you have two series: <BR>\n" );
document.write( "1, 4/9, 16/81,...<BR>\n" );
document.write( "and<BR>\n" );
document.write( "(-2/3), (-8/27)...<BR>\n" );
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document.write( "The sum of the 1st = ?<BR>\n" );
document.write( "a(1) = 1<BR>\n" );
document.write( "r = 4/9<BR>\n" );
document.write( "S = 1/(1- 4/9) = 1/(5/9) = 9/5\r<BR>\n" );
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document.write( "The sum of the 2nd = ?<BR>\n" );
document.write( "a(1) = -2/3r = (4/9)<BR>\n" );
document.write( "S = (-2/3)/[1-4/9] = (-2/3)/(5/9) = -6/5<BR>\n" );
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document.write( "Total sum = (9/5)-(6/5) = 3/5<BR>\n" );
document.write( "==================================<BR>\n" );
document.write( "Note: You can find reminders of how to handle virtually <BR>\n" );
document.write( "all math procedures by using Google on the web.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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