document.write( "Question 310597: How many liters of a 10% alcohol solution must be mixed with 50 liters of a 80% solution
\n" ); document.write( "to get a 20% solution? \n" ); document.write( "

Algebra.Com's Answer #222126 by Fombitz(32388) $\"\"$ $\"About$

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Let X be the liters of 10% solution.
\n" ); document.write( " $\"10%28X%29%2B80%2850%29=20%28X%2B50%29\"$
\n" ); document.write( " $\"10X%2B4000=20X%2B1000\"$
\n" ); document.write( " $\"-10X=-3000\"$
\n" ); document.write( " $\"X=300\"$
\n" ); document.write( "300 liters of 10% solution. \n" ); document.write( "

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