document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=310588>Question 310588</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The smaller of two integers is one-third of the larger, and their sum is greater than 100. Find the smallest possible integers.<BR>\n" );
document.write( "So far, I got this. x + 1/3 x = 100. Am I in the right direction? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #222082 by </B><A HREF=/tutors/aboutme.mpl?userid=mollukutti><B>mollukutti(30)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mollukutti><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mollukutti><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=222082\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You are in the right direction. However as this is a question related to inequalities and not equations your equation needs to be re-written as \r<BR>\n" );
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document.write( "x + 1/3 x > 100<BR>\n" );
document.write( "or, 3x+x > 300 (Multiplied either sides by 3)<BR>\n" );
document.write( "or, 4x > 300<BR>\n" );
document.write( "or, x > 75 (divided either sides by 4) </SPAN>\n" );
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