document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=310585>Question 310585</A>: <I><SPAN STYLE=\"word-break: break-all;\"> FACTORING! im not sure how to factor this correctly ive tried and have been told the answer im getting is wrong the problem is the following:\r<BR>\n" );
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document.write( "48x^2y+12xy+20xz+5x\r<BR>\n" );
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document.write( "everytime i get (4x+1)(12xy+5z)<BR>\n" );
document.write( "what am i doing wrong and what is the correct answer? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #222080 by </B><A HREF=/tutors/aboutme.mpl?userid=mollukutti><B>mollukutti(30)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mollukutti><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mollukutti><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=222080\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let us first work backwards with the answer you got:\r<BR>\n" );
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document.write( "(4x+1)(12xy+5z)<BR>\n" );
document.write( "=4x(12xy+5z)+1.(12xy+5z)<BR>\n" );
document.write( "=48x^2y + 20xz + 12xy + 5z\r<BR>\n" );
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document.write( "However the question is 48x^2y+12xy+20xz+5x which means the factors you have calculated are incorrect because your question has +5x in the end.\r<BR>\n" );
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document.write( "Now having said that lets see how we can factorize:<BR>\n" );
document.write( "48x^2y+12xy+20xz+5x<BR>\n" );
document.write( "= x(48xy+12y+20z+5)<BR>\n" );
document.write( "= x (12y(4x+1) + 5(4z+1))\r<BR>\n" );
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document.write( "This cannot be factorised further. </SPAN>\n" );
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