document.write( "Question 310517: You have a series of numbers, where the sum of the previous two numbers (except for the first two) adds up to the next one. (Like the Fibanachi sequence), the first number is 1 and the 10th number is 111. What is the second number? \n" ); document.write( "
Algebra.Com's Answer #222035 by Edwin McCravy(20056)\"\" \"About 
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document.write( "Let the 2nd number be x.  Then the numbers are\r\n" );
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document.write( "#1.  1\r\n" );
document.write( "#2.  x\r\n" );
document.write( "#3.  1+x\r\n" );
document.write( "#4.  x+(1+x)=x+1+x=1+2x\r\n" );
document.write( "#5.  (1+x)+(1+2x)=1+x+1+2x=2+3x\r\n" );
document.write( "#6.  (1+2x)+(2+3x)=1+2x+2+3x=3+5x\r\n" );
document.write( "#7.  (2+3x)+(3+5x)=2+3x+3+5x=5+8x\r\n" );
document.write( "#8.  (3+5x)+(5+8x)=3+5x+5+8x=8+13x\r\n" );
document.write( "#9.  (5+8x)+(8+13x)=5+8x+8+13x=13+21x  \r\n" );
document.write( "#10. (8+13x)+(13+21x)=8+13x+13+21x=21+34x\r\n" );
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document.write( "Since term #10 is 111:\r\n" );
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document.write( "\"21%2B34x=111\"\r\n" );
document.write( "\"34x=90\"\r\n" );
document.write( "\"x=90%2F34\"\r\n" );
document.write( "\"x=45%2F17\"\r\n" );
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document.write( "Checking, the numbers go\r\n" );
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document.write( "\"1=17%2F17\",\"45%2F17\",\"62%2F17\",\"107%2F17\",\"169%2F17\",\"276%2F17\",\"445%2F17\",\"721%2F17\",\"1166%2F17\",\"1887%2F17=111\"\r\n" );
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document.write( "Edwin

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