document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=310530>Question 310530</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The larger of the two numbers is 12 less than 5 times the smaller. If the smaller number is equal to one-third of the larger number, find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #222031 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=222031\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  The larger of the two numbers is 12 less than 5 times the smaller. If the smaller number is equal to one-third of the larger number, find the numbers.<BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "S = (1/3)L<BR>\n" );
document.write( "L = 5S-12<BR>\n" );
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document.write( "Note: L = 3S<BR>\n" );
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document.write( "Substitute for \"L\" and solve for \"S\":<BR>\n" );
document.write( "5S-12 = 3S<BR>\n" );
document.write( "2S = 12<BR>\n" );
document.write( "S = 6 (smaller)<BR>\n" );
document.write( "L = 3S = 18 (larger)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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