document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=310529>Question 310529</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in an isosceles triangle, each of the congruent sides is two thirds of the base. the perimeter of the triangle is 42. Find the length of each side of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #222028 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=222028\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> in an isosceles triangle, each of the congruent sides is two thirds of the base. the perimeter of the triangle is 42. Find the length of each side of the triangle.<BR>\n" );
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document.write( "Let the base be \"x\"<BR>\n" );
document.write( "Each equal side is (2/3)x<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "x + 2(2/3)x = 42<BR>\n" );
document.write( "x + (4/3)x = 42<BR>\n" );
document.write( "(7/3)x = 42<BR>\n" );
document.write( "(1/3)x = 6<BR>\n" );
document.write( "x = 18 (base)<BR>\n" );
document.write( "(2/3)x = 12 (each equal side)<BR>\n" );
document.write( "===========================<BR>\n" );
document.write( "cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );