document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=310454>Question 310454</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangle is 360 square meters. If the rectangles length is increased by 10 meters and the width is decreased by 6 meters, its area does not change. Find the perimeter of the originol rectangle. (Plz help me awnser this) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #222019 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=222019\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangle is 360 square meters. <BR>\n" );
document.write( "If the rectangles length is increased by 10 meters and the width is decreased <BR>\n" );
document.write( "by 6 meters, its area does not change. <BR>\n" );
document.write( "Find the perimeter of the original rectangle.<BR>\n" );
document.write( ":<BR>\n" );
document.write( "\"The area of a rectangle is 360 square meters.\"<BR>\n" );
document.write( "L * W = 360<BR>\n" );
document.write( "L = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=360%2FW ALIGN=MIDDLE  ALT=\"360%2FW\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ":<BR>\n" );
document.write( "\"If the rectangles length is increased by 10 meters and the width is decreased by 6 meters, its area does not change.\"<BR>\n" );
document.write( "(L+10)*(W-6) = 360<BR>\n" );
document.write( "FOIL<BR>\n" );
document.write( "LW - 6L + 10W - 60 = 360<BR>\n" );
document.write( "LW - 6L = -10W + 360 + 60<BR>\n" );
document.write( "L(W-6) = -10W + 420<BR>\n" );
document.write( "L = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-10W+%2B+420%29%2F%28W-6%29 ALIGN=MIDDLE  ALT=\"%28-10W+%2B+420%29%2F%28W-6%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Replace L with 360/W<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=360%2FW ALIGN=MIDDLE  ALT=\"360%2FW\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-10W+%2B+420%29%2F%28W-6%29 ALIGN=MIDDLE  ALT=\"%28-10W+%2B+420%29%2F%28W-6%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Cross multiply<BR>\n" );
document.write( "360(W-6) = W(-10W+420)<BR>\n" );
document.write( "360W - 2160 = -10W^2 + 420W<BR>\n" );
document.write( "Combine like terms on the left<BR>\n" );
document.write( "10W^2 + 360W - 420W - 2160 = 0<BR>\n" );
document.write( "10W^2 - 60W - 2160 = 0<BR>\n" );
document.write( "Simplify, divide by 10<BR>\n" );
document.write( "W^2 - 6W - 216 = 0<BR>\n" );
document.write( "Factor to<BR>\n" );
document.write( "(W-18)(W+12) = 0<BR>\n" );
document.write( "positive solution<BR>\n" );
document.write( "W = 18 m is the original width<BR>\n" );
document.write( "then<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=360%2F18 ALIGN=MIDDLE  ALT=\"360%2F18\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 20 m is the length<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Find the perimeter of the original rectangle.<BR>\n" );
document.write( "2(20) + 2(18) = 76 m <BR>\n" );
document.write( ":<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Check the area when L is increased, and W is decreased<BR>\n" );
document.write( "(20+10) * (18-6) = 360<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );