document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=310506>Question 310506</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Transport a and transport b left the loading dock at noon and headed in opposite directions. If transport a traveled at 60mph and transport b traveled at 68mph, how many hours was it before they were 348 miles apart?<BR>\n" );
document.write( "I need an equation for this kind of problem. Thank you so much! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #222017 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16949)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=222017\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Transport A speed = 60mph.<BR>\n" );
document.write( "Transport B speed = 68 mph<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Assume they travel x hours when they are 348 miles away.<BR>\n" );
document.write( "Distance traveled by transport A = 60x<BR>\n" );
document.write( "Distance traveled by transport B = 68x\r<BR>\n" );
document.write( "\n" );
document.write( "60x+68x=348<BR>\n" );
document.write( "128x=348<BR>\n" );
document.write( "x= 348/128<BR>\n" );
document.write( "x= 2.7 hours<BR>\n" );
document.write( "After 2.7 hours they will be 348 miles away </SPAN>\n" );
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